| #. Geran, just look what it says here…. No matter where it ends up, it can’t heat anything. There are three sets of water-vapor absorption lines in the near-IR spectral region. “always be held to the same temperature as the surroundings by conduction from the surrounding molecules”. Les transitions rotationnelles de la molécule agissent dans le domaine micro-ondes et infrarouge lointain. Articles like this are like microscopically examining a turd to catalog every molecule, when all we need to know is that it stinks. You are proving me right, again. CO2 does NOT “slow the cooling”. | #. Merely absorbing radiation doesn’t mean a “warming tendency”. Les bandes correspondantes … You won’t find them in the atmosphere. April 3, 2020 at 8:43 pm Then, to top it off, you try to prove me wrong by making up things. Spectre d'absorption (coefficient d'absorption en fonction de la longueur d'onde) de l'eau liquide (rouge)[1],[2], de la vapeur d'eau (vert)[3],[4],[5] et de la glace (bleu)[6],[7],[8],[9] entre 667 nm et 200 μm. Just unplug the laser and it won’t warm anything. | #, Just 2 observations about CO2 lasers — Les modèles standard utilisent des bandes d'absorption à 0.718 μm (visible), 0.810 μm (bande α), 0.935 μm bande μ), 1.13 μm (bande ρστ), 1.38 μm (bande φ), 1.88 μm (bande ψ), 2.68 μm (bande Ω), 2.90 μm (bande X). April 4, 2020 at 1:28 pm John – Geran is right that I don’t always explain myself the best. les transitions rotationnelles depuis l'IR proche (50 μm) jusqu'au domaine micro-ondes ; les transitions vibrationnelles dans l'IR moyen, de la bande μ autour de 6 μm jusqu'à la bande X à 2.9 μm ; La dernière modification de cette page a été faite le 27 mai 2020 à 06:51. April 5, 2020 at 10:58 pm Les transitions électroniques montrent une structure fine liée aux transitions vibrationnelles et rotationnelles. | #. Telephone: Calls from within the UK: 020 7419 5027. International dialling: (44) 20 7419 5027. This has nothing to do with natural uncollimated Planck radiation absorption/emission at 15 microns. So who cares what happens to the 15 micron radiation originally from the Sun? You have become infatuated with a 10 µ photon, not realizing that an ice cube emits a 10.7 µ photon at the peak of its spectrum. Reading Harrisons replies to the regulars just confirmed to me what i thought when i read the article. Harrison, you still can’t get it right. However, the better argument would be that both items are increasing the temp of their environment. | #. All of the atmosphere, including the CO2 thereof, slows the cooling of the surface. So yes, ghe violates the laws of thermodynamics. Time to move on. 2. Dans l'eau liquide les transitions rotationnelles disparaissent mais les bandes liées aux liaisons hydrogène apparaissent. For this purpose, the vibrational-rotational structure of the CO2 molecule is described. It is the acronym for “Light Amplification by Stimulated Emission of Radiation”. The wavelengths are close to those of the (000 – 0110) band and the transitions of these three bands are always observed together in the absorption spectrum. Especially the absorbed radiation power by the ground state bending mode at about 15 microns is dominant. Harrison, the GHE, as defined by the IPCC, does NOT exist. | #. That is why I would be classed as a luke-warmist because I accept that such does not contravene any laws of physics and will happen. Les modes de vibration en cisaillement de O - H conduisent à des bandes d'absorption ayant une tête de bande à 3657 cm−1 (ν1, 2.734 μm) et 3756 cm−1 (ν3, 2.662 μm) en phase gazeuse. April 5, 2020 at 11:07 pm Stand in the shade with an open view of the sky above and you will not feel any warmth arriving from the sky above, just the local ambient temperature everywhere. However, you summarily dismiss it If you had both chemistry and physics in high school, I expect you learned the physics is more mathematical than chemistry. Those near 730 and 820 nm are useful for lower tropo- spheric measurements, whereas those near 930 nm are useful for upper- tropospheric measurements... ». We are agreed that the effect will probably be pretty pathetic but you cannot just say that is your gut feeling, that is not science. The most intense ones involve excitations from the ground state to the lowest states of the bending and the asymmetric vibrations (absorption from the symmetric stretching vibration is not possible because of the absence of a dipole moment). (2) with increasing and decreasing j-values.For j = 40 this fraction is 0.012.

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